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8. $(x^{4})^{0} =$ a $x$ b $x^{4}$ c $1$ d $0$

Question

  1. $(x^{4})^{0} =$

a $x$
b $x^{4}$
c $1$
d $0$

Explanation:

Step1: Recall the exponent rule for zero power

Any non - zero number (or non - zero expression) raised to the power of 0 is equal to 1. The expression here is \((x^{4})^{0}\), and assuming \(x
eq0\) (because if \(x = 0\), \(0^{0}\) is an indeterminate form, but in the context of this problem, we can assume \(x
eq0\) as we are dealing with a standard exponent rule question), we can apply the rule \(a^{0}=1\) where \(a=x^{4}\).

Step2: Apply the zero - exponent rule

Since \(a=x^{4}\) and \(a^{0} = 1\) (for \(a
eq0\)), then \((x^{4})^{0}=1\).

Answer:

C. 1