Question

1. $\frac{3}{m - 5}cdot\frac{4m^{3}-20m^{2}}{4m^{2}}$

Explanation:

Step1: Factor the numerator of the second - fraction

Factor out \(4m^{2}\) from \(4m^{3}-20m^{2}\), we get \(4m^{2}(m - 5)\). So the expression becomes \(\frac{3}{m - 5}\cdot\frac{4m^{2}(m - 5)}{4m^{2}}\).

Step2: Cancel out the common factors

Cancel out the common factors \(m - 5\) and \(4m^{2}\) in the numerator and denominator. \(\frac{3\times\cancel{4m^{2}}\times\cancel{(m - 5)}}{(m - 5)\times\cancel{4m^{2}}}=3\).

Answer:

3