Question

3x + 1 = 7
3(____) + 1 ≟ 7
____ + 1 ≟ 7
____ = 7 √

Explanation:

Step1: Solve the equation \(3x + 1 = 7\) for \(x\)

Subtract 1 from both sides: \(3x + 1 - 1 = 7 - 1\), which simplifies to \(3x = 6\). Then divide both sides by 3: \(\frac{3x}{3}=\frac{6}{3}\), so \(x = 2\).

Step2: Substitute \(x = 2\) into the first blank

The first blank is in \(3(\underline{\quad})+1\stackrel{?}{=}7\). Substitute \(x = 2\), so we put 2 in the first blank: \(3(2)+1\stackrel{?}{=}7\).

Step3: Calculate \(3\times2\)

\(3\times2 = 6\), so the second blank (after \(3(2)\)) is 6: \(6 + 1\stackrel{?}{=}7\).

Step4: Calculate \(6 + 1\)

\(6 + 1 = 7\), so the third blank is 7: \(7 = 7\).

Answer:

First blank: \(2\), Second blank: \(6\), Third blank: \(7\) (Filling the blanks in order: \(2\), \(6\), \(7\))