Question

1. $1 + 4y + 8 + 6y - 2 + 2y = $

Explanation:

Step1: Combine constant terms

First, combine the constant terms (the terms without \( y \)): \( 1 + 8 - 2 \).
\( 1 + 8 = 9 \), then \( 9 - 2 = 7 \).

Step2: Combine like terms with \( y \)

Next, combine the terms with \( y \): \( 4y + 6y + 2y \).
\( 4y + 6y = 10y \), then \( 10y + 2y = 12y \).

Step3: Combine the results

Now, combine the result from the constant terms and the result from the \( y \)-terms: \( 7 + 12y \).

Answer:

\( 12y + 7 \)