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Question
if ( mangle rxu = 128^{circ} ), then what is ( mangle txs )?
Step1: Find the measure of $\angle 2$
Since $\angle RXU$ and $\angle 2$ are supplementary angles (they form a linear - pair), and the sum of supplementary angles is $180^{\circ}$.
If $m\angle RXU = 128^{\circ}$, then $m\angle 2=180^{\circ}-m\angle RXU$.
So, $m\angle 2 = 180^{\circ}-128^{\circ}=52^{\circ}$.
Step2: Use the vertical - angle relationship
$\angle TXS$ and $\angle 2$ are vertical angles. Vertical angles are congruent (have equal measures).
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$52^{\circ}$