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Question
does (5, 1) make the inequality 13x + 6y ≤ 16 true? yes no submit
Step1: Substitute x=5, y=1
Substitute \( x = 5 \) and \( y = 1 \) into \( 13x + 6y \):
\( 13(5) + 6(1) = 65 + 6 = 71 \)
Step2: Check inequality
Compare \( 71 \) with \( 16 \): \( 71 \leq 16 \) is false.
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