Question

lori downloaded all the pictures she took at ritas wedding into a single computer folder. she took 86 of the 134 pictures with her camera and the remainder of them with her cell phone. of the pictures lori took with her cell phone, one out of every five was blurry. to the nearest whole percent, what is the probability that when she opens a random picture from the computer folder, it will be a blurry picture she took with her cell phone? 7% 13% 31% 56%

Explanation:

Step1: Find cell phone pictures

Total pictures: 134, camera pictures: 86. So cell phone pictures: $134 - 86 = 48$.

Step2: Find blurry cell phone pictures

1 out of 5 cell phone pics is blurry. So blurry: $\frac{48}{5} = 9.6$ (wait, no—1/5 of 48: $48\times\frac{1}{5} = 9.6$? Wait, 48 divided by 5 is 9.6? Wait, 59=45, 510=50, so 48/5=9.6? Wait, no, 481/5=9.6? Wait, maybe I miscalculated. Wait, 134 - 86 = 48. Then blurry cell phone: 48(1/5) = 9.6? Wait, but total pictures are 134. So probability is (blurry cell phone)/total. So (9.6)/134 ≈ 0.0716, which is ~7%? Wait, no, wait: 48 cell phone pictures. 1/5 are blurry: 48(1/5)=9.6? Wait, 48 divided by 5 is 9.6? Wait, 59=45, 48-45=3, so 9 + 3/5 = 9.6. Then probability is 9.6 / 134 ≈ 0.0716, which is 7.16%, so ~7%. Wait, but let's check again. Total pictures: 134. Camera:86, so cell:134-86=48. Blurry cell: 48*(1/5)=9.6. Then 9.6/134 ≈ 0.0716, so 7%. So the answer is 7%.

Answer:

7% (the option with 7%)