Question

a line with a slope of $\frac{1}{7}$ passes through the point $(3, 8)$. what is its equation in point - slope form?
use the specified point in your equation. write your answer using integers, proper fractions and improper fractions. simplify all fractions.
$y - \square = \square(x - \square)$

Explanation:

Step1: Recall point - slope formula

The point - slope form of a linear equation is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope of the line.

Step2: Identify values of $m$, $x_1$, and $y_1$

We are given that the slope $m =-\frac{1}{7}$ and the point $(x_1,y_1)=(3,8)$. So $x_1 = 3$ and $y_1=8$.

Step3: Substitute values into the formula

Substitute $m =-\frac{1}{7}$, $x_1 = 3$, and $y_1 = 8$ into the point - slope formula $y - y_1=m(x - x_1)$. We get $y - 8=-\frac{1}{7}(x - 3)$.

Answer:

$y - 8=-\frac{1}{7}(x - 3)$ (So in the blanks: 8, $-\frac{1}{7}$, 3)