Question

1. the letters of the word house are to be rearranged.

6a how many different arrangements are possible?
arrangements = enter your next step here

Explanation:

Step1: Identify the number of letters

The word "HOUSE" has 5 distinct letters.

Step2: Use permutation formula for distinct objects

The number of permutations of \( n \) distinct objects is \( n! \). Here, \( n = 5 \), so we calculate \( 5! \).

Step3: Calculate \( 5! \)

\( 5! = 5\times4\times3\times2\times1 = 120 \)

Answer:

120