Question

at least one of the answers above is not correct.
find the following probabilities for the standard normal random variable z:
(a) ( p ( - 1.56 leq z leq 1.3 ) = 0.8438 )
(b) ( p ( - 1.88 leq z leq 1.02 ) = 0.816 )
(c) ( p ( z leq 2.08 ) = )
(d) ( p ( z > 69 ) = 0.9545 )
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Explanation:

Step1: Use the standard normal distribution table

The standard normal distribution table gives the cumulative probability \(P(Z\leq z)\) for a standard normal random variable \(Z\).

Step2: Find \(P(z\leq2.08)\)

Looking up the value \(z = 2.08\) in the standard - normal table. The table gives the cumulative probability from the left - hand side. For \(z=2.08\), we find the row corresponding to \(2.0\) and the column corresponding to \(0.08\).
The value in the standard - normal table for \(z = 2.08\) is \(0.9812\).

Answer:

\(0.9812\)