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7. a kite is flown so that 70 m of string is let out, and the kite has …

Question

  1. a kite is flown so that 70 m of string is let out, and the kite has a height of 45 m above the ground. what is the angle between the string and the ground?

Explanation:

Step1: Apply sine function

In a right - triangle, \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\). Here, the height of the kite (opposite side) \(h = 45\) m and the length of the string (hypotenuse) \(l=70\) m. So, \(\sin\theta=\frac{45}{70}\).

Step2: Calculate the angle

\(\theta=\sin^{- 1}(\frac{45}{70})\).
\(\theta=\sin^{-1}(0.6429)\)
Using a calculator, \(\theta\approx40^{\circ}\)

Answer:

The angle between the string and the ground is approximately \(40^{\circ}\)