QUESTION IMAGE
Question
jose and nancy both set up a proportion to find the missing width, w, of the smaller of two similar rectangles. their work is shown below.
jose’s work:
\\(\frac{3}{5} = \frac{w}{6}\\)
\\(5w = 9\\)
\\(w \approx 1.8\\)
nancy’s work:
\\(\frac{3}{w} = \frac{5}{6}\\)
\\(5w = 18\\)
\\(w \approx 3.6\\)
(image of two rectangles: first rectangle has height 3, length 5; second rectangle has height 6, width w)
which student made an error in their work and what error did they make?
\\(\circ\\) nancy did divide 18 by 5 correctly.
\\(\circ\\) jose did not multiply 3×6 correctly.
\\(\circ\\) jose did not set up the proportion correctly.
\\(\circ\\) nancy did not set up the proportion correctly
Step1: Analyze similar rectangles proportion
For similar rectangles, corresponding sides are proportional. The first rectangle has height 3 and width 5, the second has height 6 and width \( w \). So the correct proportion should relate height to width: \( \frac{3}{5}=\frac{w}{6} \) (Jose) or \( \frac{3}{w}=\frac{5}{6} \) (Nancy)? Wait, no—wait, the first rectangle: height 3, width 5. Second: height 6, width \( w \). So height of first over height of second should equal width of first over width of second? Wait, no, similar figures: ratio of corresponding sides. So first rectangle: height 3, width 5. Second: height 6, width \( w \). So \( \frac{\text{height of first}}{\text{height of second}}=\frac{\text{width of first}}{\text{width of second}} \) → \( \frac{3}{6}=\frac{5}{w} \)? Wait, no, maybe I mixed up. Wait, the first rectangle is horizontal: height 3, width 5. The second is vertical: width \( w \), height 6. So corresponding sides: first's height (3) corresponds to second's width (\( w \)), first's width (5) corresponds to second's height (6). So proportion should be \( \frac{3}{w}=\frac{5}{6} \) (Nancy) or \( \frac{3}{5}=\frac{w}{6} \) (Jose)? Wait, let's check cross - multiplication.
For Jose's proportion: \( \frac{3}{5}=\frac{w}{6} \). Cross - multiply: \( 3\times6 = 5\times w \) → \( 18 = 5w \)? Wait, but Jose wrote \( 5w = 9 \). Oh! Wait, Jose's cross - multiplication: \( 3\times6 = 18 \), but he wrote \( 5w = 9 \). Wait, no, wait the options: let's re - examine.
Wait, the options: "Jose did not multiply \( 3\times6 \) correctly." Let's check Jose's work. His proportion is \( \frac{3}{5}=\frac{w}{6} \). Cross - multiplying: \( 3\times6 = 5\times w \) → \( 18 = 5w \). But Jose wrote \( 5w = 9 \). So he made a mistake in multiplying \( 3\times6 \) (he got 9 instead of 18). Wait, but let's check the proportion setup. Wait, maybe the correct proportion is \( \frac{3}{w}=\frac{5}{6} \) (Nancy) or \( \frac{3}{5}=\frac{w}{6} \) (Jose). Wait, let's see the rectangles: first rectangle: height 3, width 5. Second: width \( w \), height 6. So if they are similar, the ratio of height to width should be the same. So for first: \( \frac{\text{height}}{\text{width}}=\frac{3}{5} \). For second: \( \frac{\text{width}}{\text{height}}=\frac{w}{6} \). Wait, no, maybe orientation. Alternatively, first rectangle's height (3) and second's width (\( w \)) are corresponding, first's width (5) and second's height (6) are corresponding. So \( \frac{3}{w}=\frac{5}{6} \) (Nancy) or \( \frac{3}{5}=\frac{w}{6} \) (Jose). Let's check cross - multiplication for both.
Jose: \( \frac{3}{5}=\frac{w}{6} \). Cross - multiply: \( 3\times6 = 5\times w \) → \( 18 = 5w \). But Jose wrote \( 5w = 9 \). So he made a mistake in \( 3\times6 \) (he calculated \( 3\times6 = 9 \) instead of 18). So the option "Jose did not multiply \( 3\times6 \) correctly" is correct? Wait, but let's check the options again.
Wait the options are:
- Nancy did divide 18 by 5 correctly. (Nancy's \( 5w = 18 \), \( w=\frac{18}{5}=3.6 \), which is correct. So this is wrong.)
- Jose did not multiply \( 3\times6 \) correctly. (Jose's \( 3\times6 \) should be 18, but he got 9, so this is correct.)
- Jose did not set up the proportion correctly. (Is his proportion setup wrong? Let's see: if the first rectangle has height 3 and width 5, second has width \( w \) and height 6, the proportion \( \frac{3}{5}=\frac{w}{6} \) is a valid proportion (relating height of first to width of first, and width of second to height of second). So setup is correct, but cross - multiplication is wrong. So…
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Jose did not multiply \( 3\times6 \) correctly.