QUESTION IMAGE
Question
8.
∠jkm = 4x + 5
∠mkl = 6x + 15
∠jkl is a straight angle
find x
Step1: Set up the equation
Since \(\angle JKL\) is a straight angle (\(180^{\circ}\)), and \(\angle JKM+\angle MKL = \angle JKL\), we have \((4x + 5)+(6x + 15)=180\).
Step2: Simplify the left - hand side
Combine like terms: \(4x+6x+5 + 15=180\), which simplifies to \(10x+20 = 180\).
Step3: Solve for \(x\)
Subtract \(20\) from both sides: \(10x=180 - 20\), so \(10x=160\). Then divide both sides by \(10\): \(x=\frac{160}{10}\).
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\(x = 16\)