Question

jake is planning a trip to china. he has made a list of cities he would like to visit, as well as the approximate amount of money he plans to spend in each as a result of travel, lodging, shopping, and so on. all costs are listed in renminbi (\yen).

unfortunately, jake only has \yen2,920 available. what is the cheapest city that jake can remove from his travel plans and still stay under budget?
a. tianjin
b. wuhan
c. nanjing
d. beijing

Explanation:

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<reasoning>

Calculate total cost of all cities

Using the Table Reading knowledge point
\[

$$\begin{aligned} \text{Total Cost} &= 557 + 681 + 595 + 728 + 449 + 534 \\ &= 3544 \end{aligned}$$

\]

Determine required cost reduction

To stay under the budget of \(¥2,920\), we calculate the minimum amount that must be saved:
\[

$$\begin{aligned} \text{Required Reduction} &= \text{Total Cost} - \text{Budget} \\ &= 3544 - 2920 \\ &= 624 \end{aligned}$$

\]

Identify eligible cities for removal

To stay under budget, Jake must remove a city that costs at least \(¥624\). We list the cities and their costs:

• Tianjin: \(¥557\) (too low)
• Nanjing: \(¥681\) (eligible)
• Zhengzhou: \(¥595\) (too low)
• Beijing: \(¥728\) (eligible)
• Wuhan: \(¥449\) (too low)
• Chengdu: \(¥534\) (too low)

Select the cheapest eligible city

Among the eligible cities that cost at least \(¥624\) (Nanjing at \(¥681\) and Beijing at \(¥728\)), we find the cheapest one to minimize the impact on his plans:
\[
681 < 728
\]
Thus, Nanjing is the cheapest city he can remove.
</reasoning>

<answer>
<mcq-option>a. Tianjin</mcq-option>
<mcq-option>b. Wuhan</mcq-option>
<mcq-correct>c. Nanjing</mcq-correct>
<mcq-option>d. Beijing</mcq-option>
</answer>

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"question_type": "Multiple Choice",
"knowledge_point": [
"Mathematics",
"Algebra",
"Budget Optimization"
]
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</post_analysis>

Answer:

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<reasoning>

Calculate total cost of all cities

Using the Table Reading knowledge point
\[

$$\begin{aligned} \text{Total Cost} &= 557 + 681 + 595 + 728 + 449 + 534 \\ &= 3544 \end{aligned}$$

\]

Determine required cost reduction

To stay under the budget of \(¥2,920\), we calculate the minimum amount that must be saved:
\[

$$\begin{aligned} \text{Required Reduction} &= \text{Total Cost} - \text{Budget} \\ &= 3544 - 2920 \\ &= 624 \end{aligned}$$

\]

Identify eligible cities for removal

To stay under budget, Jake must remove a city that costs at least \(¥624\). We list the cities and their costs:

• Tianjin: \(¥557\) (too low)
• Nanjing: \(¥681\) (eligible)
• Zhengzhou: \(¥595\) (too low)
• Beijing: \(¥728\) (eligible)
• Wuhan: \(¥449\) (too low)
• Chengdu: \(¥534\) (too low)

Select the cheapest eligible city

Among the eligible cities that cost at least \(¥624\) (Nanjing at \(¥681\) and Beijing at \(¥728\)), we find the cheapest one to minimize the impact on his plans:
\[
681 < 728
\]
Thus, Nanjing is the cheapest city he can remove.
</reasoning>

<answer>
<mcq-option>a. Tianjin</mcq-option>
<mcq-option>b. Wuhan</mcq-option>
<mcq-correct>c. Nanjing</mcq-correct>
<mcq-option>d. Beijing</mcq-option>
</answer>

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