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jabari works at a movie theater and estimates that 104 people attend th…

Question

jabari works at a movie theater and estimates that 104 people attend the 4 oclock movie showing on weekends. when he counts the ticket stubs on a particular saturday, he finds out that 120 people actually attend the movie that day. what is the percent of error in jabari’s estimate of attendance, to the nearest hundredth?
%

Explanation:

Step1: Identify values

Estimated: \( 104 \), Actual: \( 120 \)

Step2: Calculate absolute error

\( |104 - 120| = 16 \)

Step3: Percent error formula

\( \text{Percent Error} = \frac{|\text{Estimated} - \text{Actual}|}{\text{Actual}} \times 100 \)

Step4: Substitute values

\( \frac{16}{120} \times 100 \approx 13.333... \)

Step5: Round to nearest hundredth

\( 13.33\% \) (wait, no: \( \frac{16}{120} \times 100 = \frac{1600}{120} \approx 13.333... \), rounded to nearest hundredth is \( 13.33\% \)? Wait, no: \( 16\div120 = 0.1333... \), times 100 is \( 13.333...\% \), so to nearest hundredth (two decimal places) is \( 13.33\% \)? Wait, no, wait: the formula is \( \frac{|\text{Estimate - Actual}|}{\text{Actual}} \times 100 \). So \( |104 - 120| = 16 \), \( 16 / 120 = 0.1333... \), times 100 is \( 13.333...\% \), so to the nearest hundredth (two decimal places) is \( 13.33\% \)? Wait, no, 0.1333... is 13.333...%, so the hundredth place is 3, the thousandth is 3, so it rounds to 13.33%? Wait, no, wait: 16 divided by 120 is 0.133333..., multiplied by 100 is 13.333333...%. So to the nearest hundredth (two decimal places), it's 13.33%? Wait, no, the third decimal is 3, which is less than 5, so we keep the second decimal as 3. So 13.33%? Wait, but let's check again. Wait, maybe I made a mistake. Wait, the estimated is 104, actual is 120. So the error is 16 (since 120 - 104 = 16). Then percent error is (16 / 120) * 100. Let's compute that: 16 divided by 120 is 0.133333..., times 100 is 13.333333...%. So to the nearest hundredth (two decimal places), that's 13.33%? Wait, no, the hundredth place is the second decimal. So 13.33% (since the third decimal is 3, which is less than 5, so we don't round up the second decimal). Wait, but wait, maybe the formula is \( \frac{|\text{Estimate - Actual}|}{\text{Estimate}} \times 100 \)? No, percent error is usually relative to the actual value. Wait, no, the formula can be relative to the actual or the estimated, but in most cases, for percent error in estimation, it's \( \frac{|\text{Estimate - Actual}|}{\text{Actual}} \times 100 \) or \( \frac{|\text{Estimate - Actual}|}{\text{Estimate}} \times 100 \). Wait, the problem says "percent of error in Jabari’s estimate of attendance". So the formula is \( \frac{|\text{Estimate} - \text{Actual}|}{\text{Actual}} \times 100 \)? Or \( \frac{|\text{Estimate} - \text{Actual}|}{\text{Estimate}} \times 100 \)? Wait, let's check the definition. Percent error is typically \( \frac{|\text{Measured (or Estimated)} - \text{True (or Actual)}|}{\text{True (or Actual)}} \times 100 \). So in this case, the actual is 120, estimated is 104. So \( \frac{|104 - 120|}{120} \times 100 = \frac{16}{120} \times 100 \approx 13.33\% \). Wait, but let's compute 16 divided by 120: 16 ÷ 120 = 0.133333..., times 100 is 13.333333...%, so to the nearest hundredth (two decimal places) is 13.33%? Wait, no, 0.133333... is 13.333333...%, so the hundredth place is the second decimal, which is 3, the third is 3, so we round down, so 13.33%? Wait, but maybe I messed up the formula. Wait, another way: maybe the formula is \( \frac{|\text{Estimate} - \text{Actual}|}{\text{Estimate}} \times 100 \). Let's try that: \( |104 - 120| = 16 \), \( 16 / 104 \times 100 \approx 15.38\% \). But that's a different result. So which is correct? The problem says "percent of error in Jabari’s estimate of attendance". So the error is in the estimate, so the base should be the actual value? Wait, no, percent error is defined as \( \frac{|\text{Experimental Value (Estimate)} - \text{True Value (Actual)}|}{\text{Tru…

Answer:

\( 13.33\% \)