Question

for item 4, use the information to answer the question. 4. a figure has vertices l(3, 4), m(-3, 7) and n(-6, 0) and is translated to form the image with vertices l(1, 8), m(-5, 11), and n(-8, 4). how did the x - and y - values of each coordinate change using this translation?

Explanation:

Step1: Calculate change in x - value for point L

For point L, original x - value is $x_{L}=3$ and new x - value is $x_{L'}=1$. The change in x - value $\Delta x_{L}=x_{L'}-x_{L}=1 - 3=-2$.

Step2: Calculate change in x - value for point M

For point M, original x - value is $x_{M}=-3$ and new x - value is $x_{M'}=-5$. The change in x - value $\Delta x_{M}=x_{M'}-x_{M}=-5-(-3)=-2$.

Step3: Calculate change in x - value for point N

For point N, original x - value is $x_{N}=-6$ and new x - value is $x_{N'}=-8$. The change in x - value $\Delta x_{N}=x_{N'}-x_{N}=-8-(-6)=-2$.

Step4: Calculate change in y - value for point L

For point L, original y - value is $y_{L}=4$ and new y - value is $y_{L'}=8$. The change in y - value $\Delta y_{L}=y_{L'}-y_{L}=8 - 4 = 4$.

Step5: Calculate change in y - value for point M

For point M, original y - value is $y_{M}=7$ and new y - value is $y_{M'}=11$. The change in y - value $\Delta y_{M}=y_{M'}-y_{M}=11 - 7 = 4$.

Step6: Calculate change in y - value for point N

For point N, original y - value is $y_{N}=0$ and new y - value is $y_{N'}=4$. The change in y - value $\Delta y_{N}=y_{N'}-y_{N}=4-0 = 4$.

Answer:

The x - values changed by $- 2$ and the y - values changed by $4$.