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(interpreting independence lc) p(a) = 0.33 and p(b) = 0.44. determine p…

Question

(interpreting independence lc) p(a) = 0.33 and p(b) = 0.44. determine p(a|b) if events a and b are independent. 0.15 0.33 0.44 0.77

Explanation:

Step1: Recall the formula for conditional probability when events are independent

If \(A\) and \(B\) are independent events, then \(P(A|B)=\frac{P(A\cap B)}{P(B)}\), and for independent events \(P(A\cap B)=P(A)\times P(B)\). So \(P(A|B) = P(A)\) (by substituting \(P(A\cap B)=P(A)\times P(B)\) into the conditional - probability formula: \(P(A|B)=\frac{P(A)\times P(B)}{P(B)}\), and \(P(B)
eq0\)).

Step2: Substitute the given value of \(P(A)\)

Given \(P(A) = 0.33\).

Answer:

\(0.33\)