Question

iew: find the speed of the gondola.

Explanation:

Step1: Find the speed formula

Speed \(v=\frac{\text{Distance}(d)}{\text{Time}(t)}\).

Step2: Calculate the speed

Given \(t = 3\) s and \(d=16.5\) ft. Then \(v=\frac{16.5}{3}=5.5\) ft/s.

Step3: Find distance at \(t = 1\) s

Using \(d=v\times t\), when \(t = 1\) s and \(v = 5.5\) ft/s, \(d=5.5\times1 = 5.5\) ft.

Step4: Find distance at \(t = 2\) s

Using \(d=v\times t\), when \(t = 2\) s and \(v = 5.5\) ft/s, \(d=5.5\times2=11\) ft.

Answer:

The speed of the gondola is \(5.5\) ft/s. The distance at \(t = 1\) s is \(5.5\) ft and at \(t = 2\) s is \(11\) ft.