Question

hw
name:
adr. alg
does the point(s) lie
on the line?
① circle all points that lie on ( y = \frac{1}{2}x + 3 )
a) ( (\frac{1}{2}, - 3) )

Explanation:

Step1: Substitute \(x = 2\) into the equation \(y=\frac{1}{2}x + 3\)

Substitute \(x = 2\) into \(y=\frac{1}{2}x+3\), we get \(y=\frac{1}{2}\times2+3\).

Step2: Calculate the value of \(y\)

First, calculate \(\frac{1}{2}\times2 = 1\), then \(y=1 + 3=4\).

Answer:

Since when \(x = 2\), \(y = 4
eq-3\), the point \((2,-3)\) does not lie on the line \(y=\frac{1}{2}x + 3\).