Question

hugo picked some peaches from his tree. he weighed each of the peaches. the results are shown in the line plot. what is the total weight of the two heaviest peaches? line plot with weights: 5/8, 5/8, 7/8, 1, 1 1/8, 1 2/8, 1 3/8 a 3 3/4 pounds b 1 5/8 pounds c 2 3/4 pounds d 2 5/8 pounds

Explanation:

Step1: Identify heaviest weights

The two heaviest weights from the line plot are \(1\frac{2}{8}\) and \(1\frac{3}{8}\) pounds.

Step2: Convert to improper fractions

\(1\frac{2}{8}=\frac{10}{8}\), \(1\frac{3}{8}=\frac{11}{8}\)

Step3: Add the fractions

\(\frac{10}{8}+\frac{11}{8}=\frac{21}{8}\)

Step4: Convert back to mixed number

\(\frac{21}{8}=2\frac{5}{8}\)? Wait, no, wait. Wait, maybe I misread the weights. Wait, the x - axis labels: let's check again. Wait, the rightmost two are \(1\frac{2}{8}\) and \(1\frac{3}{8}\)? Wait, no, maybe the labels are \(1\frac{2}{8}\) (which is \(1\frac{1}{4}\)) and \(1\frac{3}{8}\)? Wait, no, let's recalculate. Wait, \(1\frac{2}{8}+1\frac{3}{8}=(1 + 1)+(\frac{2}{8}+\frac{3}{8})=2+\frac{5}{8}=2\frac{5}{8}\)? But the options have \(2\frac{5}{8}\) as D? Wait, no, wait the first calculation was wrong. Wait, let's list the weights:

Looking at the line plot, the weights are: \(\frac{5}{8}\), \(\frac{6}{8}\), \(1\), \(1\frac{1}{8}\) (wait, no, the marks: the first x at \(\frac{5}{8}\), second at \(\frac{6}{8}\), then at \(1\), then multiple at \(1\frac{1}{8}\), then at \(1\frac{2}{8}\), then at \(1\frac{3}{8}\). So the two heaviest are \(1\frac{2}{8}\) (which is \(\frac{10}{8}\)) and \(1\frac{3}{8}\) (which is \(\frac{11}{8}\)). Adding them: \(\frac{10}{8}+\frac{11}{8}=\frac{21}{8}=2\frac{5}{8}\). Wait, but option D is \(2\frac{5}{8}\) pounds. Wait, but let's check the options again. Wait, maybe I made a mistake in the weights. Wait, \(1\frac{2}{8}\) is \(1\frac{1}{4}\) and \(1\frac{3}{8}\):

\(1\frac{2}{8}+1\frac{3}{8}=1+\frac{2}{8}+1+\frac{3}{8}=2+\frac{5}{8}=2\frac{5}{8}\). Yes, so the total weight is \(2\frac{5}{8}\) pounds.

Answer:

D. \(2\frac{5}{8}\) pounds