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Find the perpendicular slope
The given line is \(y = 4x\), which has a slope of \(m_1 = 4\).
Since line \(L\) is perpendicular to this line, its slope \(m\) is the negative reciprocal:
$$
m = -\frac{1}{4}
$$
Identify the given point
From the graph, line \(L\) passes through the labeled point:
$$
(x_1, y_1) = (1, 4)
$$
Write in point-slope form
The point-slope form of a linear equation is:
$$
y - y_1 = m(x - x_1)
$$
Substituting \(m = -\frac{1}{4}\) and the point \((1, 4)\):
$$
y - 4 = -\frac{1}{4}(x - 1)
$$
Convert to slope-intercept form
To convert to slope-intercept form \(y = mx + b\), solve for \(y\):
$$
y - 4 = -\frac{1}{4}x + \frac{1}{4}
$$
$$
y = -\frac{1}{4}x + \frac{1}{4} + 4
$$
$$
y = -\frac{1}{4}x + \frac{17}{4}
$$
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Question 1
Write an equation for line L in point-slope form:
$$y - 4 = -\frac{1}{4}(x - 1)$$
Question 2
Write an equation for line L in slope-intercept form:
$$y = -\frac{1}{4}x + \frac{17}{4}$$