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Step1: Analyze the first inequality \( y < -\frac{1}{2}x + 5 \)
The boundary line is \( y = -\frac{1}{2}x + 5 \), which has a slope of \( -\frac{1}{2} \) and a y - intercept of 5. Since the inequality is \( y < \), we shade below this line, and the line should be dashed (because it's a strict inequality, \( y
eq-\frac{1}{2}x + 5 \)).
Step2: Analyze the second inequality \( y\geq-\frac{1}{2}x - 1 \)
The boundary line is \( y = -\frac{1}{2}x - 1 \), which has a slope of \( -\frac{1}{2} \) and a y - intercept of - 1. Since the inequality is \( y\geq \), we shade above this line, and the line should be solid (because it's a non - strict inequality, \( y = -\frac{1}{2}x - 1 \) is included in the solution set).
Step3: Analyze the relationship between the two lines
The two lines \( y = -\frac{1}{2}x+5 \) and \( y = -\frac{1}{2}x - 1 \) are parallel (since they have the same slope, \( m = -\frac{1}{2} \)) and the region shaded below \( y = -\frac{1}{2}x + 5 \) and the region shaded above \( y=-\frac{1}{2}x - 1 \) will overlap (because the line \( y = -\frac{1}{2}x+5 \) is above the line \( y=-\frac{1}{2}x - 1 \) for all x - values).
Now let's analyze each option:
- Option A: The graph does not seem to represent the correct shading for the two inequalities.
- Option B: The graph does not represent the correct shading for the two parallel lines with the correct regions.
- Option C: The two parallel lines with the region between them (the overlapping region of the two shaded areas) is the solution set. The line \( y = -\frac{1}{2}x+5 \) is dashed (for \( y<-\frac{1}{2}x + 5 \)) and \( y=-\frac{1}{2}x - 1 \) is solid (for \( y\geq-\frac{1}{2}x - 1 \)), and the overlapping region is the set of points that satisfy both inequalities.
- Option D: Since the two lines are parallel and the shaded regions overlap, there are solutions.
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C (the option with the description "infinite number of solutions" and the corresponding graph)