Question

1. how can you find the product? use partial products to 879 × 3 3 × 879 = (3 × 800) + (3 × 3) + (3 × 9) 3 × 879 = 2,700 + + 3 × 879 =

Explanation:

Step1: Decompose 879

We break down 879 into its place - value components. 879 can be written as \(800 + 70+9\). So, when we multiply \(3\times879\) using the distributive property (partial products), we have \(3\times879=(3\times800)+(3\times70)+(3\times9)\).

Step2: Calculate each partial product

• For \(3\times800\), we know that \(3\times8 = 24\), so \(3\times800 = 2400\).
• For \(3\times70\), since \(3\times7 = 21\), then \(3\times70=210\).
• For \(3\times9\), we get \(3\times9 = 27\).

Step3: Sum the partial products

Now, we add up these partial products: \(2400+210 + 27\). First, \(2400+210=2610\), and then \(2610 + 27=2637\).

Filling in the blanks:
\(3\times879=(3\times\boldsymbol{800})+(3\times\boldsymbol{70})+(3\times\boldsymbol{9})\)
\(3\times879=\boldsymbol{2400}+\boldsymbol{210}+\boldsymbol{27}\)
\(3\times879=\boldsymbol{2637}\)

Answer:

The completed blanks are: \(800\), \(70\), \(9\); \(2400\), \(210\), \(27\); and the final product is \(2637\). So the last blank (for \(3\times879\)) is \(\boldsymbol{2637}\)