Question

homework 12 in week 7: the coordinate plane
question 3, 2.1.21
hw score: 16.67%, 2 of 12 parts
points 0 of 1
find the distance ( d ( p _ { 1 }, p _ { 2 } ) ) between the given points ( p _ { 1 } ) and ( p _ { 2 } ).
( p _ { 1 } = ( 6,2 ) )
( p _ { 2 } = ( - 8,2 ) )
( d ( p _ { 1 }, p _ { 2 } ) = square )
(simplify your answer. type an exact answer, using radicals as needed.)

Explanation:

Step1: Identify the coordinates

Given \(P_1=(6,2)\) and \(P_2 = (-8,2)\). The distance formula between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). Here \(x_1 = 6,y_1=2,x_2=-8,y_2 = 2\).

Step2: Substitute into the distance formula

Substitute the values into the formula:

$$
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$$

Step3: Simplify the square - root

Since \(\sqrt{196}=14\)

Answer:

\(14\)