Question

△hij is rotated 270° clockwise about the origin to produce △hij. write the rule for the rotation. (x, y) ↦ (□, □)

Explanation:

Step1: Recall rotation rules

The rule for a \(270^{\circ}\) clockwise rotation about the origin is \((x,y)\to(y, -x)\).

Step2: Verify with points

Take point \(H(-7,-4)\). After rotation, \(H'\) should be \((-4,7)\) (but wait, no, correct rule: for \(270^{\circ}\) clockwise, if original point \((x,y)\), new \(x'\) is \(y\), new \(y'\) is \(-x\). Let's check \(I(0,0)\): \((0,0)\to(0,0)\) (correct). Take \(J(-3,-5)\): using \((x,y)\to(y, -x)\), we get \(J'(-5,3)\) (matches graph).

Answer:

\((x,y)\to(y, -x)\)