Question

the height of a mythical beast, in feet, t years after birth is given by the function $h(t) = \sqrt{3t + 5}$. what is the height of the mythical beast, in feet, at $t = 9$ years after birth? round to one decimal place.
show your work here
hint: to add an exponent ($x^n$), type exponent or press ^

Explanation:

Step1: Substitute t = 9 into the function

We have the function \( h(t)=\sqrt{3t + 5} \). Substitute \( t = 9 \) into it, so we get \( h(9)=\sqrt{3\times9 + 5} \).

Step2: Calculate the expression inside the square root

First, calculate \( 3\times9=27 \), then \( 27 + 5 = 32 \). So now the function becomes \( h(9)=\sqrt{32} \).

Step3: Calculate the square root and round

We know that \( \sqrt{32}\approx5.65685 \). Rounding to one decimal place, we look at the second decimal digit which is 5. Since 5 is greater than or equal to 5, we round up the first decimal digit. So \( 5.65685\approx5.7 \).

Answer:

5.7