Question

hector, a soup chef at a new restaurant, kept track of the first days soup sales. split pea chicken noodle cup 5 6 bowl 6 3 what is the probability that a randomly selected soup was not ordered in a bowl and was not split pea? simplify any fractions.

Explanation:

Step1: Calculate total number of soups

Add all the values in the table: \(5 + 6+6 + 3=\boldsymbol{20}\)

Step2: Find the number of soups that meet the criteria

We want soups that are not in a bowl (so cups) and not split - pea (so chicken noodle cup). The number of chicken noodle cups is \(6\)

Step3: Calculate the probability

Probability \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). Here, \(P = \frac{6}{20}\)

Step4: Simplify the fraction

Divide numerator and denominator by \(2\): \(\frac{6\div2}{20\div2}=\frac{3}{10}\)

Answer:

\(\frac{3}{10}\)