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Question
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midsegments of triangles
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what is ( m angle e f d )?
Step1: Use the triangle angle - sum property
In \(\triangle DEY\), we know one angle is \(45^{\circ}\) and another is \(75^{\circ}\). The sum of angles in a triangle is \(180^{\circ}\). Let the third angle in \(\triangle DEY\) be \( \angle DYE\). So, \( \angle DYE=180-(45 + 75)\).
Step2: Use the mid - segment and parallel line properties
Since \(ZY\) and \(XY\) are mid - segments (by the markings of equal segments), \(ZY\parallel EF\) and \(XY\parallel DF\). Then, quadrilateral \(ZDFY\) is a parallelogram (a quadrilateral with both pairs of opposite sides parallel). In a parallelogram, opposite angles are equal. So, \(m\angle EFD=m\angle DYE\)
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