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Question
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midsegments of triangles
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what is ( m angle e f d )?
×60
Step1: Find the third angle of triangle \( \triangle DEY \)
The sum of angles in a triangle is \( 180^{\circ} \). In \( \triangle DEY \), if one angle is \( 45^{\circ} \) and another is \( 75^{\circ} \), then the third angle \( \angle DYE=180-(45 + 75)=60^{\circ} \).
Step2: Use the mid - segment property
Since \( ZY \) is a mid - segment (by the equal segment marks), \( \triangle DZY\sim\triangle DEF \) (by the mid - segment theorem which states that a line segment joining the mid - points of two sides of a triangle is parallel to the third side and half its length, and the triangles are similar). Corresponding angles of similar triangles are equal. So \( m\angle EFD=m\angle DZY \). Also, \( \angle DZY\) and \( \angle DYE\) are corresponding angles (because of the parallel lines and transversal properties from the mid - segment).
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\( 60^{\circ} \)