Question

1. graph triangle jkl after a translation left 1 unit and down 5 units.

Explanation:

Step1: Determine the original coordinates

• Point \(J(4,5)\)
• Point \(K(5,1)\)
• Point \(L(1,1)\)

Step2: Apply the translation rule

The translation rule for moving left \(1\) unit (subtract \(1\) from \(x\)-coordinate) and down \(5\) units (subtract \(5\) from \(y\)-coordinate) is \((x,y)\to(x - 1,y-5)\)

• For point \(J\): \((4-1,5 - 5)=(3,0)\)
• For point \(K\): \((5-1,1 - 5)=(4,-4)\)
• For point \(L\): \((1-1,1 - 5)=(0,-4)\)

Step3: Plot the new points

Plot the points \(J'(3,0)\), \(K'(4,-4)\) and \(L'(0,-4)\) on the coordinate - plane and connect them to form the translated triangle.

Answer:

The new coordinates of the triangle \(J'KL'\) are \(J'(3,0)\), \(K'(4,-4)\) and \(L'(0,-4)\). Plot these points and connect them.