Question

graph the point (-2.5, -2.5) on the coordinate plane.

Explanation:

Step1: Identify x-coordinate

The x - coordinate of the point \((-2.5, - 2.5)\) is \(-2.5\). On the x - axis, we move 2.5 units to the left of the origin (since it's negative). Each grid line on the x - axis represents 1 unit, so halfway between \(-2\) and \(-3\) (because \(-2.5=-2 - 0.5\)) is the x - position.

Step2: Identify y-coordinate

The y - coordinate of the point \((-2.5, - 2.5)\) is \(-2.5\). On the y - axis, we move 2.5 units down from the origin (since it's negative). Each grid line on the y - axis represents 1 unit, so halfway between \(-2\) and \(-3\) (because \(-2.5=-2 - 0.5\)) is the y - position.

Step3: Plot the point

The point \((-2.5, - 2.5)\) is located at the intersection of the vertical line through \(-2.5\) on the x - axis and the horizontal line through \(-2.5\) on the y - axis. So we mark the point that is halfway between the grid points \((-2,-2)\), \((-2,-3)\), \((-3,-2)\) and \((-3,-3)\).

Answer:

The point \((-2.5, - 2.5)\) is plotted at the position halfway between \((-2,-2)\), \((-2,-3)\), \((-3,-2)\) and \((-3,-3)\) on the coordinate plane. (Visually, it's the point in the third quadrant, halfway between the integer - valued grid points around \(x = - 2.5\) and \(y=-2.5\))