Question

graph the point (-1.5, 4.5) on the coordinate plane.

Explanation:

Step1: Identify x - coordinate

The x - coordinate of the point \((-1.5,4.5)\) is \(- 1.5\). On the x - axis, we move 1.5 units to the left of the origin (since the x - coordinate is negative). Each grid line on the x - axis represents an integer value. The distance between \(-2\) and \(-1\) is 1 unit, so the mid - point between \(-2\) and \(-1\) is \(-1.5\).

Step2: Identify y - coordinate

The y - coordinate of the point \((-1.5,4.5)\) is \(4.5\). On the y - axis, we move 4.5 units up from the origin (since the y - coordinate is positive). The distance between \(4\) and \(5\) is 1 unit, so the mid - point between \(4\) and \(5\) is \(4.5\).

Step3: Plot the point

First, locate the position on the x - axis corresponding to \(x=-1.5\) (mid - way between \(-2\) and \(-1\)) and then locate the position on the y - axis corresponding to \(y = 4.5\) (mid - way between \(4\) and \(5\)). The intersection of the vertical line through \(x=-1.5\) and the horizontal line through \(y = 4.5\) is the point \((-1.5,4.5)\).

(Note: Since this is a graph - plotting problem, the final answer is the plotted point at the intersection of \(x=-1.5\) (mid - way between \(-2\) and \(-1\)) and \(y = 4.5\) (mid - way between \(4\) and \(5\)) on the coordinate plane.)

Answer:

The point \((-1.5,4.5)\) is plotted at the location 1.5 units left of the origin on the x - axis and 4.5 units up on the y - axis (mid - way between \(-2\) and \(-1\) on the x - axis and mid - way between \(4\) and \(5\) on the y - axis).