Question

graph the parabola.
$y = \frac{1}{4}x^2$
plot five points on the parabola: the vertex, two points to the left of the vertex function button.

Explanation:

Step1: Find the vertex

For $y=\frac{1}{4}x^2$, vertex is $(0,0)$ (since $x=0$ gives $y=0$).

Step2: Calculate left points ($x=-2,-4$)

• $x=-2$: $y=\frac{1}{4}(-2)^2=1$ → $(-2,1)$
• $x=-4$: $y=\frac{1}{4}(-4)^2=4$ → $(-4,4)$

Step3: Calculate right points ($x=2,4$)

• $x=2$: $y=\frac{1}{4}(2)^2=1$ → $(2,1)$
• $x=4$: $y=\frac{1}{4}(4)^2=4$ → $(4,4)$

Answer:

Five points: $(0,0)$, $(-2,1)$, $(-4,4)$, $(2,1)$, $(4,4)$
(Plot these points and draw the parabola.)