Question

graph the image of trapezoid defg after a translation 8 units left and 11 units down.

Explanation:

Step1: Find the coordinates of the original points

Assume \(D(4,1)\), \(E(8,1)\), \(F(6,9)\), \(G(-2,9)\)

Step2: Apply the translation rule

The translation rule for \(8\) units left (subtract \(8\) from \(x -\) coordinate) and \(11\) units down (subtract \(11\) from \(y -\) coordinate) is \((x,y)\to(x - 8,y-11)\)

• For point \(D(4,1)\):

\(x=4-8=-4\), \(y = 1-11=-10\), new point \(D'(-4,-10)\)

• For point \(E(8,1)\):

\(x=8 - 8=0\), \(y=1-11=-10\), new point \(E'(0,-10)\)

• For point \(F(6,9)\):

\(x=6-8=-2\), \(y=9 - 11=-2\), new point \(F'(-2,-2)\)

• For point \(G(-2,9)\):

\(x=-2-8=-10\), \(y=9-11=-2\), new point \(G'(-10,-2)\)

Step3: Plot the new points

Plot \(D'(-4,-10)\), \(E'(0,-10)\), \(F'(-2,-2)\), \(G'(-10,-2)\) on the coordinate plane and connect them to form the translated trapezoid.

Answer:

Plot the points \(D'(-4,-10)\), \(E'(0,-10)\), \(F'(-2,-2)\), \(G'(-10,-2)\) and connect them.