Question

graph the image of square jklm after a translation 10 units left and 3 units down.

Explanation:

Step1: Recall translation rule

For a point $(x,y)$ translated 10 units left and 3 units down, the new - point is $(x - 10,y - 3)$.

Step2: Identify original coordinates

Assume $J(0,-2)$, $K(10,-2)$, $L(10,8)$, $M(0,8)$.

Step3: Calculate new coordinates

For point $J$: $x=0,y = - 2$, new coordinates are $(0 - 10,-2 - 3)=(-10,-5)$.
For point $K$: $x = 10,y=-2$, new coordinates are $(10 - 10,-2 - 3)=(0,-5)$.
For point $L$: $x = 10,y = 8$, new coordinates are $(10 - 10,8 - 3)=(0,5)$.
For point $M$: $x = 0,y = 8$, new coordinates are $(0 - 10,8 - 3)=(-10,5)$.

Step4: Graph new square

Plot the points $(-10,-5)$, $(0,-5)$, $(0,5)$, $(-10,5)$ and connect them to form the new square.

Answer:

Graph the square with vertices $(-10,-5)$, $(0,-5)$, $(0,5)$, $(-10,5)$.