Question

graph the image of square bcde after a dilation with a scale factor of 2, centered at the origin.

Explanation:

Step1: Identify original coordinates

From the graph: $B(-4,-2)$, $C(3,-2)$, $D(3,5)$, $E(-4,5)$

Step2: Apply dilation rule

Dilation centered at origin: $(x,y) \to (2x,2y)$
$B' = 2(-4,-2) = (-8,-4)$
$C' = 2(3,-2) = (6,-4)$
$D' = 2(3,5) = (6,10)$
$E' = 2(-4,5) = (-8,10)$

Step3: Plot new points

Connect $B'(-8,-4)$, $C'(6,-4)$, $D'(6,10)$, $E'(-8,10)$ to form the dilated square.

Answer:

The image of square BCDE after dilation has vertices at $(-8,-4)$, $(6,-4)$, $(6,10)$, and $(-8,10)$. Plot these points and connect them to get the dilated square.