Question

graph the image of square abcd after a dilation with a scale factor of 3, centered at the origin.

Explanation:

Step1: Identify original coordinates

From graph: A(-3,-3), B(1,-3), C(1,1), D(-3,1)

Step2: Apply dilation rule

Multiply each coordinate by scale factor 3:
$A' = (-3×3, -3×3) = (-9,-9)$
$B' = (1×3, -3×3) = (3,-9)$
$C' = (1×3, 1×3) = (3,3)$
$D' = (-3×3, 1×3) = (-9,3)$

Step3: Plot new points

Graph $A'(-9,-9)$, $B'(3,-9)$, $C'(3,3)$, $D'(-9,3)$ and connect them.

Answer:

The image of square ABCD after dilation has vertices at (-9,-9), (3,-9), (3,3), (-9,3) (plot these points to form the dilated square).