Question

graph the image of \\( \delta c d e \\) after a translation 7 units left and 5 units down.

Explanation:

Step1: Find coordinates of original points

Assume \( C(1,-3) \), \( D(3,-3) \), \( E(4,5) \).

Step2: Apply translation rule

The translation rule for \( 7 \) units left (\( x - 7 \)) and \( 5 \) units down (\( y - 5 \)).
For point \( C \): \( x=1 - 7=-6 \), \( y=-3 - 5=-8 \), so \( C'(-6,-8) \).
For point \( D \): \( x = 3-7=-4 \), \( y=-3 - 5=-8 \), so \( D'(-4,-8) \).
For point \( E \): \( x=4 - 7=-3 \), \( y=5 - 5 = 0 \), so \( E'(-3,0) \).

Step3: Plot new points and connect

Plot \( C'(-6,-8) \), \( D'(-4,-8) \), \( E'(-3,0) \) on the coordinate - plane and connect them to form \( \triangle C'D'E' \).

Answer:

Plot the points \( C'(-6,-8) \), \( D'(-4,-8) \), \( E'(-3,0) \) and connect them.