Question

graph the image of $\triangle jkl$ after a reflection over the line $y=-x$.

Explanation:

Step1: Find coordinates of \( J,K,L \)

From the graph, \( J(2,5) \), \( K(2,8) \), \( L(4,4) \).

Step2: Apply reflection rule over \( y = -x \)

The rule for reflection over \( y=-x \) is \( (x,y)\to(-y,-x) \).
For \( J(2,5) \):
\( (2,5)\to(-5,-2) \)
For \( K(2,8) \):
\( (2,8)\to(-8,-2) \)
For \( L(4,4) \):
\( (4,4)\to(-4,-4) \)

Step3: Plot the new points

Plot \( J'(-5,-2) \), \( K'(-8,-2) \), \( L'(-4,-4) \) and connect them to form \( \triangle J'K'L' \).

Answer:

Plot the points \( (-5,-2) \), \( (-8,-2) \), \( (-4,-4) \) and connect them to get the reflected triangle.