Question

the graph of the discrete probability to the right represents the number of live births by a mother 48 to 51 years old who had a live birth in 2015. complete parts (a) through (d) below
(a) what is the probability that a randomly selected 48 - to 51 year - old mother who had a live birth in 2015 has had her fourth live birth in that year?
0.112 (type an integer or a decimal)
(b) what is the probability that a randomly selected 48 - to 51 - year - old mother who had a live birth in 2015 has had her fourth or fifth live birth in that year?
(type an integer or a decimal)

Explanation:

Step1: Identify probabilities from the graph

From the graph, the probability of having a fourth - live birth \(P(4)=0.112\) and the probability of having a fifth - live birth \(P(5) = 0.104\)

Step2: Use the addition rule for mutually - exclusive events

For mutually - exclusive events \(A\) and \(B\) (in this case, \(A\) is having a fourth - live birth and \(B\) is having a fifth - live birth), the probability \(P(A\cup B)=P(A)+P(B)\)

Substitute \(P(4) = 0.112\) and \(P(5)=0.104\) into the formula:

\(P(4\cup5)=0.112 + 0.104\)

\(P(4\cup5)=0.216\)

Answer:

\(0.216\)