QUESTION IMAGE
Question
- given $f(x) = 3x - 5$, which statement is true?
a) $f(0) = 0$
b) $f(3) = 4$
c) $f(4) = 3$
d) $f(5) = 0$
- the height of a ball hit into the air is modeled by the equation $h = -16t^2 + 48t$, where $h$ represents the height, in feet, and $t$ represents the number of seconds that have passed since the ball was hit. what is the height of the ball after 2 seconds?
- the function $g(x)$ is defined as $g(x) = -2x^2 + 3x$. the value of $g(-3)$ is:
- given $f(x) = 2x + 3$, find the value of $x$ when:
a) $f(x) = 1$
b) $f(x) = 23$
- the graph of $y = f(x)$ is shown below.
which point could be used to find $f(2)$?
graph of a coordinate plane with points a, b, c, d
Question 5
Step1: Check option a: Calculate \( f(0) \)
To find \( f(0) \), substitute \( x = 0 \) into \( f(x)=3x - 5 \).
\( f(0)=3(0)-5=-5
eq0 \), so option a is false.
Step2: Check option b: Calculate \( f(3) \)
Substitute \( x = 3 \) into \( f(x)=3x - 5 \).
\( f(3)=3(3)-5 = 9 - 5=4 \), so option b is true.
Step3: Check option c: Calculate \( f(4) \)
Substitute \( x = 4 \) into \( f(x)=3x - 5 \).
\( f(4)=3(4)-5=12 - 5 = 7
eq3 \), so option c is false.
Step4: Check option d: Calculate \( f(5) \)
Substitute \( x = 5 \) into \( f(x)=3x - 5 \).
\( f(5)=3(5)-5=15 - 5 = 10
eq0 \), so option d is false.
Step1: Substitute \( t = 2 \) into the equation \( h=-16t^{2}+48t \)
We need to find the height \( h \) when \( t = 2 \). So we substitute \( t = 2 \) into the given formula.
\( h=-16(2)^{2}+48(2) \)
Step2: Calculate the value of \( h \)
First, calculate \( (2)^{2}=4 \), then \( -16\times4=-64 \) and \( 48\times2 = 96 \). Then add these two results: \( h=-64 + 96=32 \).
Step1: Substitute \( x=-3 \) into \( g(x)=-2x^{2}+3x \)
To find \( g(-3) \), we replace \( x \) with \( -3 \) in the function \( g(x) \).
\( g(-3)=-2(-3)^{2}+3(-3) \)
Step2: Calculate the value of \( g(-3) \)
First, calculate \( (-3)^{2}=9 \), then \( -2\times9=-18 \) and \( 3\times(-3)=-9 \). Then add these two results: \( g(-3)=-18-9=-27 \).
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b) \( f(3)=4 \)