Question

given rhombus defg below. if m∠ehf = (-x - 3)°, solve for x.

Explanation:

Step1: Recall property of rhombus diagonals

In a rhombus, the diagonals are perpendicular to each other. So, \(m\angle EHF = 90^{\circ}\).

Step2: Set up the equation

We have the equation \(-x - 3=90\).

Step3: Solve for \(x\)

Add \(3\) to both sides: \(-x=90 + 3\), so \(-x=93\). Multiply both sides by \(- 1\) to get \(x=-93\).

Answer:

\(x = - 93\)