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Question
- given: \\(\overline{pq} \cong \overline{rs}\\)\\(\overline{pq} \perp \overline{qs}\\)\\(\overline{rs} \perp \overline{qs}\\)prove: \\(\overline{ps} \cong \overline{rq}\\)\\(\
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Step1: Identify Right Angles
Since \(\overline{PQ} \perp \overline{QS}\) and \(\overline{RS} \perp \overline{QS}\), \(\angle PQS = 90^\circ\) and \(\angle RSQ = 90^\circ\). So, \(\triangle PQS\) and \(\triangle RSQ\) are right triangles.
Step2: Identify Common Side
\(\overline{QS}\) is a common side to both \(\triangle PQS\) and \(\triangle RSQ\), so \(\overline{QS} \cong \overline{SQ}\) (reflexive property).
Step3: Apply SAS Congruence
We know \(\overline{PQ} \cong \overline{RS}\) (given), \(\angle PQS \cong \angle RSQ\) (both right angles), and \(\overline{QS} \cong \overline{SQ}\) (reflexive). By the Side - Angle - Side (SAS) congruence criterion, \(\triangle PQS \cong \triangle RSQ\).
Step4: Corresponding Parts of Congruent Triangles
Since \(\triangle PQS \cong \triangle RSQ\), their corresponding sides \(\overline{PS}\) and \(\overline{RQ}\) are congruent. So, \(\overline{PS} \cong \overline{RQ}\).
Now, filling in the proof table:
| Statements | Reasons |
|---|---|
| 2. \(\angle PQS = 90^\circ\), \(\angle RSQ = 90^\circ\) | 2. Definition of perpendicular lines |
| 3. \(\angle PQS \cong \angle RSQ\) | 3. All right angles are congruent |
| 4. \(\overline{QS} \cong \overline{SQ}\) | 4. Reflexive property of congruence |
| 5. \(\triangle PQS \cong \triangle RSQ\) | 5. SAS (Side - Angle - Side) congruence criterion |
| 6. \(\overline{PS} \cong \overline{RQ}\) | 6. Corresponding parts of congruent triangles are congruent (CPCTC) |
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The proof is completed by showing \(\triangle PQS \cong \triangle RSQ\) using SAS and then using CPCTC to conclude \(\overline{PS} \cong \overline{RQ}\), with the steps filled in the table as above.