Question

given the building layout for store a, store b, store c, and store d, what portion of the shared $6000 security costs should be apportioned to store d? a 2500 ft² b 625 ft² c 625 ft² d 2500 ft² apportioned cost = $?

Explanation:

Step1: Calculate total area

First, find the total area of all stores. Store A: \(2500\) \(ft^2\), Store B: \(625\) \(ft^2\), Store C: \(625\) \(ft^2\), Store D: \(2500\) \(ft^2\). Total area \(= 2500 + 625 + 625 + 2500 = 6250\) \(ft^2\).

Step2: Find proportion of Store D

The proportion of Store D's area to total area is \(\frac{2500}{6250}\).

Step3: Calculate cost for Store D

Multiply this proportion by total security cost (\(6000\)). So, \(6000\times\frac{2500}{6250}\). Simplify \(\frac{2500}{6250}=\frac{2}{5}\), then \(6000\times\frac{2}{5}= 2400\).

Answer:

\(2400\)