Question

give a counterexample if the conjecture is false. suppose x = 2, then -x = select choice

Explanation:

Step1: Understand the Conjecture

The conjecture here seems to be related to the value of \(-x\) when \(x = 2\), but we need to find a counterexample if the conjecture is false. Wait, maybe the original conjecture is something like "If \(x\) is a number, then \(-x\) has a certain property", but with \(x = 2\) given. Wait, maybe the conjecture is "If \(x = 2\), then \(-x = 2\)"? Let's check. If \(x = 2\), then \(-x=- 2\), which is not equal to \(2\). So a counterexample would be when \(x = 2\), \(-x=-2
eq2\). Wait, maybe the problem is to check if the statement "If \(x = 2\), then \(-x=\) [some value]" is false. Let's assume the conjecture is "If \(x = 2\), then \(-x = 2\)". Then a counterexample is \(x = 2\), and \(-x=-2\), which shows the conjecture is false.

Step1: Identify the Conjecture

Assume the conjecture is: If \(x = 2\), then \(-x = 2\).

Step2: Find a Counterexample

For \(x = 2\), calculate \(-x\): \(-x=-2\). Since \(-2
eq2\), when \(x = 2\), \(-x=-2\) which is not equal to \(2\). So this is a counterexample.

Answer:

When \(x = 2\), \(-x=-2
eq2\) (so the counterexample is \(x = 2\) where \(-x=-2\) showing the conjecture (if it was \(-x = 2\) when \(x = 2\)) is false).