Question

give the center and radius of the circle described by the equation and graph the equation. use the graph to identify the relations domain and range. (x - 3)^2 + (y - 6)^2 = 4 what is the center of the circle? the circle is centered at the point. (type an ordered pair.)

Explanation:

Step1: Recall the standard form of a circle's equation

The standard form of a circle's equation is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center of the circle and \(r\) is the radius.

Step2: Identify \(h\) and \(k\)

For the given equation \((x - 3)^2+(y - 6)^2 = 4\), comparing with \((x - h)^2+(y - k)^2=r^2\), we have \(h = 3\) and \(k=6\).

Answer:

\((3,6)\)