Question

a genetic experiment involving peas yielded one sample of offspring consisting of 438 green peas and 120 yellow. use a 0.01 significance level to test the claim that under the same circumstances, 24% of offspring peas will be. identify the null hypothesis, alternative hypothesis, test statistic, p - value, conclusion about the null hypothesis, a final conclusion that addresses the original claim. use the p - value method and the normal distribution as an approximation to the binomial distribution. what is the test statistic? z = - 1.38 (round to two decimal places as needed.) what is the p - value? p - value = (round to three decimal places as needed.)

Explanation:

Step1: Determine the type of test

Since the alternative hypothesis is \(H_1: p
eq0.24\), this is a two - tailed test.

Step2: Calculate the P - value

For a two - tailed test with test statistic \(z=-1.38\), the P - value is \(2\times(1 - P(Z\leq|z|))\).
Using the standard normal distribution table or a calculator, \(P(Z\leq1.38)=0.9162\).
So, \(P - value=2\times(1 - 0.9162)=2\times0.0838 = 0.168\)

Answer:

\(P - value = 0.168\)