Question

the function f is defined as follows.

f(x)=sqrt3{x - 2}

find f(-62) and f(29).

f(-62)=square

f(29)=square

Explanation:

Step1: Substitute $x = - 62$ into $f(x)$

$f(-62)=\sqrt[3]{-62 - 2}=\sqrt[3]{-64}$

Step2: Calculate the cube - root of $-64$

Since $(-4)\times(-4)\times(-4)=-64$, $\sqrt[3]{-64}=-4$

Step3: Substitute $x = 29$ into $f(x)$

$f(29)=\sqrt[3]{29 - 2}=\sqrt[3]{27}$

Step4: Calculate the cube - root of $27$

Since $3\times3\times3 = 27$, $\sqrt[3]{27}=3$

Answer:

$f(-62)=-4$
$f(29)=3$