Question

fruit mass
biscuit mass
the table shows the mass, in grams, of fruit and biscuits that the zoo fed two of the monkeys.
based on the ratio, complete the missing values in the table.
monkey fruit mass (g) biscuit mass (g)
a 28

b 45

Explanation:

Step1: Determine the ratio

From the diagram, fruit mass has 7 units and biscuit mass has 5 units. So the ratio of fruit mass to biscuit mass is \( 7:5 \).

Step2: Solve for Monkey A's biscuit mass

Let the biscuit mass for Monkey A be \( x \). Using the ratio \( \frac{\text{Fruit mass}}{\text{Biscuit mass}}=\frac{7}{5} \), we substitute fruit mass = 28:

$$ \frac{28}{x}=\frac{7}{5} $$

Cross - multiply: \( 7x = 28\times5 \)
\( 7x=140 \)
Divide both sides by 7: \( x = \frac{140}{7}=20 \)

Step3: Solve for Monkey B's fruit mass

Let the fruit mass for Monkey B be \( y \). Using the ratio \( \frac{y}{45}=\frac{7}{5} \)
Cross - multiply: \( 5y = 45\times7 \)
\( 5y = 315 \)
Divide both sides by 5: \( y=\frac{315}{5} = 63 \)

Answer:

For Monkey A, the biscuit mass is 20 g. For Monkey B, the fruit mass is 63 g.