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Question
four relations are shown below. click on the tabs to see them. relation 1 relation 2 relation 3 relation 4 domain range sun 4 sky -5 door tree -8 check the box corresponding to each relation that represents a function. ☐ relation 1 ☐ relation 2 ☐ relation 3 ☐ relation 4 ☐ none of the relations
Step1: Recall the definition of a function
A function is a relation where each element in the domain is paired with exactly one element in the range. In other words, no two different ordered pairs in the relation have the same first element (domain element) with different second elements (range elements).
Step2: Analyze Relation 1
For Relation 1, let's list the mappings:
- sun is mapped to -5
- sky is mapped to -5
- door is mapped to 4
- tree is mapped to -8
Wait, no, looking at the diagram: Wait, the domain elements are sun, sky, door, tree. Let's check each domain element:
- sun: where does it point? Let's see the arrows. Sun points to -5? Wait, no, the arrows: sun's arrow, sky's arrow, door's arrow, tree's arrow. Wait, actually, in a function, each domain element (input) must have exactly one range element (output). So for each of sun, sky, door, tree, we check if they have only one arrow.
Looking at the diagram:
- sun: one arrow (to -5? Wait, no, let's re-examine. Wait, the domain is sun, sky, door, tree. The range is 4, -5, -8. Wait, the arrows: sun → -5? sky → -5? door → 4? tree → -8? Wait, no, maybe I misread. Wait, the original diagram: sun, sky, door, tree (domain) and 4, -5, -8 (range). Let's check each domain element:
- sun: how many arrows? One. So sun is paired with one range element.
- sky: one arrow. Paired with one range element.
- door: one arrow. Paired with one range element.
- tree: one arrow. Paired with one range element.
Wait, but wait, is that correct? Wait, maybe I made a mistake. Wait, the key is: in a function, each domain element has exactly one range element. So even if two domain elements map to the same range element (like sun and sky both mapping to -5), that's allowed (it's a many-to-one relation, which is a function). The only thing not allowed is one domain element mapping to multiple range elements (one-to-many), which is not a function.
So for Relation 1: each domain element (sun, sky, door, tree) has exactly one arrow (one range element). So Relation 1 is a function? Wait, no, wait the diagram: let's look again. Wait, the user's diagram:
Domain: sun, sky, door, tree
Range: 4, -5, -8
Arrows:
sun → -5?
sky → -5?
door → 4?
tree → -8?
Wait, but then sun and sky both map to -5 (many-to-one), which is allowed in a function. So each domain element has one range element. So Relation 1 is a function? Wait, but maybe I misread the arrows. Wait, maybe the arrows are:
sun → -8?
sky → -5?
door → 4?
tree → -5?
No, the original problem's diagram: "sun", "sky", "door", "tree" (domain) and "4", "-5", "-8" (range). The arrows: sun's arrow, sky's arrow, door's arrow, tree's arrow. Let's assume that each domain element has exactly one arrow (one range value). So sun: 1 arrow, sky: 1 arrow, door: 1 arrow, tree: 1 arrow. Therefore, each domain element is paired with exactly one range element, so Relation 1 is a function.
But wait, the problem has four relations, but only Relation 1 is shown. Wait, the user's image shows Relation 1, and the other relations (2,3,4) are tabs, but the user hasn't shown them. Wait, the question is to check the box for each relation that represents a function. But since only Relation 1 is shown, but the user's problem might have a mistake? Wait, no, maybe the original problem (from the user's image) is that Relation 1: let's check again. Wait, maybe I made a mistake. Wait, the domain elements are sun, sky, door, tree (four elements), range elements are 4, -5, -8 (three elements). So some range elements are mapped by multiple domain elements (many-to-one), which is…
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$\boxed{\text{Relation 1}}$ (assuming only Relation 1 is a function based on the given diagram; if other relations were shown and they were not functions, but since we only have Relation 1's diagram, we conclude Relation 1 is a function)